- Was mache ich falsch?
8^(x-9)= 4^x
(x-9) log 8 = x log 4
x log 8 - 9 log 8 = x log 4 /-x log 8
-9 log 8 = x log 4 - x log 8
-9 log 8 = x (log 4- log 8)
-9 log 8 / (log 4 - log 8) = x
Bekomme aber die falsche Lösung raus? Was mache ich falsch?
DANKE